3.7.81 \(\int \frac {x^2 (c+d x)^{3/2}}{\sqrt {a+b x}} \, dx\)

Optimal. Leaf size=254 \[ \frac {(b c-a d)^2 \left (35 a^2 d^2+10 a b c d+3 b^2 c^2\right ) \tanh ^{-1}\left (\frac {\sqrt {d} \sqrt {a+b x}}{\sqrt {b} \sqrt {c+d x}}\right )}{64 b^{9/2} d^{5/2}}+\frac {\sqrt {a+b x} \sqrt {c+d x} (b c-a d) \left (35 a^2 d^2+10 a b c d+3 b^2 c^2\right )}{64 b^4 d^2}+\frac {\sqrt {a+b x} (c+d x)^{3/2} \left (35 a^2 d^2+10 a b c d+3 b^2 c^2\right )}{96 b^3 d^2}-\frac {\sqrt {a+b x} (c+d x)^{5/2} (7 a d+3 b c)}{24 b^2 d^2}+\frac {x \sqrt {a+b x} (c+d x)^{5/2}}{4 b d} \]

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Rubi [A]  time = 0.23, antiderivative size = 254, normalized size of antiderivative = 1.00, number of steps used = 7, number of rules used = 6, integrand size = 22, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.273, Rules used = {90, 80, 50, 63, 217, 206} \begin {gather*} \frac {\sqrt {a+b x} (c+d x)^{3/2} \left (35 a^2 d^2+10 a b c d+3 b^2 c^2\right )}{96 b^3 d^2}+\frac {\sqrt {a+b x} \sqrt {c+d x} (b c-a d) \left (35 a^2 d^2+10 a b c d+3 b^2 c^2\right )}{64 b^4 d^2}+\frac {(b c-a d)^2 \left (35 a^2 d^2+10 a b c d+3 b^2 c^2\right ) \tanh ^{-1}\left (\frac {\sqrt {d} \sqrt {a+b x}}{\sqrt {b} \sqrt {c+d x}}\right )}{64 b^{9/2} d^{5/2}}-\frac {\sqrt {a+b x} (c+d x)^{5/2} (7 a d+3 b c)}{24 b^2 d^2}+\frac {x \sqrt {a+b x} (c+d x)^{5/2}}{4 b d} \end {gather*}

Antiderivative was successfully verified.

[In]

Int[(x^2*(c + d*x)^(3/2))/Sqrt[a + b*x],x]

[Out]

((b*c - a*d)*(3*b^2*c^2 + 10*a*b*c*d + 35*a^2*d^2)*Sqrt[a + b*x]*Sqrt[c + d*x])/(64*b^4*d^2) + ((3*b^2*c^2 + 1
0*a*b*c*d + 35*a^2*d^2)*Sqrt[a + b*x]*(c + d*x)^(3/2))/(96*b^3*d^2) - ((3*b*c + 7*a*d)*Sqrt[a + b*x]*(c + d*x)
^(5/2))/(24*b^2*d^2) + (x*Sqrt[a + b*x]*(c + d*x)^(5/2))/(4*b*d) + ((b*c - a*d)^2*(3*b^2*c^2 + 10*a*b*c*d + 35
*a^2*d^2)*ArcTanh[(Sqrt[d]*Sqrt[a + b*x])/(Sqrt[b]*Sqrt[c + d*x])])/(64*b^(9/2)*d^(5/2))

Rule 50

Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_), x_Symbol] :> Simp[((a + b*x)^(m + 1)*(c + d*x)^n)/(b*
(m + n + 1)), x] + Dist[(n*(b*c - a*d))/(b*(m + n + 1)), Int[(a + b*x)^m*(c + d*x)^(n - 1), x], x] /; FreeQ[{a
, b, c, d}, x] && NeQ[b*c - a*d, 0] && GtQ[n, 0] && NeQ[m + n + 1, 0] &&  !(IGtQ[m, 0] && ( !IntegerQ[n] || (G
tQ[m, 0] && LtQ[m - n, 0]))) &&  !ILtQ[m + n + 2, 0] && IntLinearQ[a, b, c, d, m, n, x]

Rule 63

Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_), x_Symbol] :> With[{p = Denominator[m]}, Dist[p/b, Sub
st[Int[x^(p*(m + 1) - 1)*(c - (a*d)/b + (d*x^p)/b)^n, x], x, (a + b*x)^(1/p)], x]] /; FreeQ[{a, b, c, d}, x] &
& NeQ[b*c - a*d, 0] && LtQ[-1, m, 0] && LeQ[-1, n, 0] && LeQ[Denominator[n], Denominator[m]] && IntLinearQ[a,
b, c, d, m, n, x]

Rule 80

Int[((a_.) + (b_.)*(x_))*((c_.) + (d_.)*(x_))^(n_.)*((e_.) + (f_.)*(x_))^(p_.), x_Symbol] :> Simp[(b*(c + d*x)
^(n + 1)*(e + f*x)^(p + 1))/(d*f*(n + p + 2)), x] + Dist[(a*d*f*(n + p + 2) - b*(d*e*(n + 1) + c*f*(p + 1)))/(
d*f*(n + p + 2)), Int[(c + d*x)^n*(e + f*x)^p, x], x] /; FreeQ[{a, b, c, d, e, f, n, p}, x] && NeQ[n + p + 2,
0]

Rule 90

Int[((a_.) + (b_.)*(x_))^2*((c_.) + (d_.)*(x_))^(n_.)*((e_.) + (f_.)*(x_))^(p_.), x_Symbol] :> Simp[(b*(a + b*
x)*(c + d*x)^(n + 1)*(e + f*x)^(p + 1))/(d*f*(n + p + 3)), x] + Dist[1/(d*f*(n + p + 3)), Int[(c + d*x)^n*(e +
f*x)^p*Simp[a^2*d*f*(n + p + 3) - b*(b*c*e + a*(d*e*(n + 1) + c*f*(p + 1))) + b*(a*d*f*(n + p + 4) - b*(d*e*(
n + 2) + c*f*(p + 2)))*x, x], x], x] /; FreeQ[{a, b, c, d, e, f, n, p}, x] && NeQ[n + p + 3, 0]

Rule 206

Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> Simp[(1*ArcTanh[(Rt[-b, 2]*x)/Rt[a, 2]])/(Rt[a, 2]*Rt[-b, 2]), x]
/; FreeQ[{a, b}, x] && NegQ[a/b] && (GtQ[a, 0] || LtQ[b, 0])

Rule 217

Int[1/Sqrt[(a_) + (b_.)*(x_)^2], x_Symbol] :> Subst[Int[1/(1 - b*x^2), x], x, x/Sqrt[a + b*x^2]] /; FreeQ[{a,
b}, x] &&  !GtQ[a, 0]

Rubi steps

\begin {align*} \int \frac {x^2 (c+d x)^{3/2}}{\sqrt {a+b x}} \, dx &=\frac {x \sqrt {a+b x} (c+d x)^{5/2}}{4 b d}+\frac {\int \frac {(c+d x)^{3/2} \left (-a c-\frac {1}{2} (3 b c+7 a d) x\right )}{\sqrt {a+b x}} \, dx}{4 b d}\\ &=-\frac {(3 b c+7 a d) \sqrt {a+b x} (c+d x)^{5/2}}{24 b^2 d^2}+\frac {x \sqrt {a+b x} (c+d x)^{5/2}}{4 b d}+\frac {\left (3 b^2 c^2+10 a b c d+35 a^2 d^2\right ) \int \frac {(c+d x)^{3/2}}{\sqrt {a+b x}} \, dx}{48 b^2 d^2}\\ &=\frac {\left (3 b^2 c^2+10 a b c d+35 a^2 d^2\right ) \sqrt {a+b x} (c+d x)^{3/2}}{96 b^3 d^2}-\frac {(3 b c+7 a d) \sqrt {a+b x} (c+d x)^{5/2}}{24 b^2 d^2}+\frac {x \sqrt {a+b x} (c+d x)^{5/2}}{4 b d}+\frac {\left ((b c-a d) \left (3 b^2 c^2+10 a b c d+35 a^2 d^2\right )\right ) \int \frac {\sqrt {c+d x}}{\sqrt {a+b x}} \, dx}{64 b^3 d^2}\\ &=\frac {(b c-a d) \left (3 b^2 c^2+10 a b c d+35 a^2 d^2\right ) \sqrt {a+b x} \sqrt {c+d x}}{64 b^4 d^2}+\frac {\left (3 b^2 c^2+10 a b c d+35 a^2 d^2\right ) \sqrt {a+b x} (c+d x)^{3/2}}{96 b^3 d^2}-\frac {(3 b c+7 a d) \sqrt {a+b x} (c+d x)^{5/2}}{24 b^2 d^2}+\frac {x \sqrt {a+b x} (c+d x)^{5/2}}{4 b d}+\frac {\left ((b c-a d)^2 \left (3 b^2 c^2+10 a b c d+35 a^2 d^2\right )\right ) \int \frac {1}{\sqrt {a+b x} \sqrt {c+d x}} \, dx}{128 b^4 d^2}\\ &=\frac {(b c-a d) \left (3 b^2 c^2+10 a b c d+35 a^2 d^2\right ) \sqrt {a+b x} \sqrt {c+d x}}{64 b^4 d^2}+\frac {\left (3 b^2 c^2+10 a b c d+35 a^2 d^2\right ) \sqrt {a+b x} (c+d x)^{3/2}}{96 b^3 d^2}-\frac {(3 b c+7 a d) \sqrt {a+b x} (c+d x)^{5/2}}{24 b^2 d^2}+\frac {x \sqrt {a+b x} (c+d x)^{5/2}}{4 b d}+\frac {\left ((b c-a d)^2 \left (3 b^2 c^2+10 a b c d+35 a^2 d^2\right )\right ) \operatorname {Subst}\left (\int \frac {1}{\sqrt {c-\frac {a d}{b}+\frac {d x^2}{b}}} \, dx,x,\sqrt {a+b x}\right )}{64 b^5 d^2}\\ &=\frac {(b c-a d) \left (3 b^2 c^2+10 a b c d+35 a^2 d^2\right ) \sqrt {a+b x} \sqrt {c+d x}}{64 b^4 d^2}+\frac {\left (3 b^2 c^2+10 a b c d+35 a^2 d^2\right ) \sqrt {a+b x} (c+d x)^{3/2}}{96 b^3 d^2}-\frac {(3 b c+7 a d) \sqrt {a+b x} (c+d x)^{5/2}}{24 b^2 d^2}+\frac {x \sqrt {a+b x} (c+d x)^{5/2}}{4 b d}+\frac {\left ((b c-a d)^2 \left (3 b^2 c^2+10 a b c d+35 a^2 d^2\right )\right ) \operatorname {Subst}\left (\int \frac {1}{1-\frac {d x^2}{b}} \, dx,x,\frac {\sqrt {a+b x}}{\sqrt {c+d x}}\right )}{64 b^5 d^2}\\ &=\frac {(b c-a d) \left (3 b^2 c^2+10 a b c d+35 a^2 d^2\right ) \sqrt {a+b x} \sqrt {c+d x}}{64 b^4 d^2}+\frac {\left (3 b^2 c^2+10 a b c d+35 a^2 d^2\right ) \sqrt {a+b x} (c+d x)^{3/2}}{96 b^3 d^2}-\frac {(3 b c+7 a d) \sqrt {a+b x} (c+d x)^{5/2}}{24 b^2 d^2}+\frac {x \sqrt {a+b x} (c+d x)^{5/2}}{4 b d}+\frac {(b c-a d)^2 \left (3 b^2 c^2+10 a b c d+35 a^2 d^2\right ) \tanh ^{-1}\left (\frac {\sqrt {d} \sqrt {a+b x}}{\sqrt {b} \sqrt {c+d x}}\right )}{64 b^{9/2} d^{5/2}}\\ \end {align*}

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Mathematica [A]  time = 0.69, size = 209, normalized size = 0.82 \begin {gather*} \frac {\sqrt {c+d x} \left (\frac {3 \left (35 a^2 d^2+10 a b c d+3 b^2 c^2\right ) (b c-a d)^{3/2} \sinh ^{-1}\left (\frac {\sqrt {d} \sqrt {a+b x}}{\sqrt {b c-a d}}\right )}{\sqrt {\frac {b (c+d x)}{b c-a d}}}+\sqrt {d} \sqrt {a+b x} \left (-105 a^3 d^3+5 a^2 b d^2 (29 c+14 d x)-a b^2 d \left (15 c^2+92 c d x+56 d^2 x^2\right )+b^3 \left (-9 c^3+6 c^2 d x+72 c d^2 x^2+48 d^3 x^3\right )\right )\right )}{192 b^4 d^{5/2}} \end {gather*}

Antiderivative was successfully verified.

[In]

Integrate[(x^2*(c + d*x)^(3/2))/Sqrt[a + b*x],x]

[Out]

(Sqrt[c + d*x]*(Sqrt[d]*Sqrt[a + b*x]*(-105*a^3*d^3 + 5*a^2*b*d^2*(29*c + 14*d*x) - a*b^2*d*(15*c^2 + 92*c*d*x
+ 56*d^2*x^2) + b^3*(-9*c^3 + 6*c^2*d*x + 72*c*d^2*x^2 + 48*d^3*x^3)) + (3*(b*c - a*d)^(3/2)*(3*b^2*c^2 + 10*
a*b*c*d + 35*a^2*d^2)*ArcSinh[(Sqrt[d]*Sqrt[a + b*x])/Sqrt[b*c - a*d]])/Sqrt[(b*(c + d*x))/(b*c - a*d)]))/(192
*b^4*d^(5/2))

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IntegrateAlgebraic [A]  time = 0.55, size = 370, normalized size = 1.46 \begin {gather*} \frac {(b c-a d)^2 \left (35 a^2 d^2+10 a b c d+3 b^2 c^2\right ) \tanh ^{-1}\left (\frac {\sqrt {d} \sqrt {a+b x}}{\sqrt {b} \sqrt {c+d x}}\right )}{64 b^{9/2} d^{5/2}}-\frac {\sqrt {a+b x} (b c-a d)^2 \left (-279 a^2 b^3 d^2+\frac {511 a^2 b^2 d^3 (a+b x)}{c+d x}+\frac {105 a^2 d^5 (a+b x)^3}{(c+d x)^3}-\frac {385 a^2 b d^4 (a+b x)^2}{(c+d x)^2}-\frac {33 b^4 c^2 d (a+b x)}{c+d x}+30 a b^4 c d-\frac {33 b^3 c^2 d^2 (a+b x)^2}{(c+d x)^2}+\frac {146 a b^3 c d^2 (a+b x)}{c+d x}+\frac {9 b^2 c^2 d^3 (a+b x)^3}{(c+d x)^3}-\frac {110 a b^2 c d^3 (a+b x)^2}{(c+d x)^2}+\frac {30 a b c d^4 (a+b x)^3}{(c+d x)^3}+9 b^5 c^2\right )}{192 b^4 d^2 \sqrt {c+d x} \left (b-\frac {d (a+b x)}{c+d x}\right )^4} \end {gather*}

Antiderivative was successfully verified.

[In]

IntegrateAlgebraic[(x^2*(c + d*x)^(3/2))/Sqrt[a + b*x],x]

[Out]

-1/192*((b*c - a*d)^2*Sqrt[a + b*x]*(9*b^5*c^2 + 30*a*b^4*c*d - 279*a^2*b^3*d^2 + (9*b^2*c^2*d^3*(a + b*x)^3)/
(c + d*x)^3 + (30*a*b*c*d^4*(a + b*x)^3)/(c + d*x)^3 + (105*a^2*d^5*(a + b*x)^3)/(c + d*x)^3 - (33*b^3*c^2*d^2
*(a + b*x)^2)/(c + d*x)^2 - (110*a*b^2*c*d^3*(a + b*x)^2)/(c + d*x)^2 - (385*a^2*b*d^4*(a + b*x)^2)/(c + d*x)^
2 - (33*b^4*c^2*d*(a + b*x))/(c + d*x) + (146*a*b^3*c*d^2*(a + b*x))/(c + d*x) + (511*a^2*b^2*d^3*(a + b*x))/(
c + d*x)))/(b^4*d^2*Sqrt[c + d*x]*(b - (d*(a + b*x))/(c + d*x))^4) + ((b*c - a*d)^2*(3*b^2*c^2 + 10*a*b*c*d +
35*a^2*d^2)*ArcTanh[(Sqrt[d]*Sqrt[a + b*x])/(Sqrt[b]*Sqrt[c + d*x])])/(64*b^(9/2)*d^(5/2))

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fricas [A]  time = 1.42, size = 546, normalized size = 2.15 \begin {gather*} \left [\frac {3 \, {\left (3 \, b^{4} c^{4} + 4 \, a b^{3} c^{3} d + 18 \, a^{2} b^{2} c^{2} d^{2} - 60 \, a^{3} b c d^{3} + 35 \, a^{4} d^{4}\right )} \sqrt {b d} \log \left (8 \, b^{2} d^{2} x^{2} + b^{2} c^{2} + 6 \, a b c d + a^{2} d^{2} + 4 \, {\left (2 \, b d x + b c + a d\right )} \sqrt {b d} \sqrt {b x + a} \sqrt {d x + c} + 8 \, {\left (b^{2} c d + a b d^{2}\right )} x\right ) + 4 \, {\left (48 \, b^{4} d^{4} x^{3} - 9 \, b^{4} c^{3} d - 15 \, a b^{3} c^{2} d^{2} + 145 \, a^{2} b^{2} c d^{3} - 105 \, a^{3} b d^{4} + 8 \, {\left (9 \, b^{4} c d^{3} - 7 \, a b^{3} d^{4}\right )} x^{2} + 2 \, {\left (3 \, b^{4} c^{2} d^{2} - 46 \, a b^{3} c d^{3} + 35 \, a^{2} b^{2} d^{4}\right )} x\right )} \sqrt {b x + a} \sqrt {d x + c}}{768 \, b^{5} d^{3}}, -\frac {3 \, {\left (3 \, b^{4} c^{4} + 4 \, a b^{3} c^{3} d + 18 \, a^{2} b^{2} c^{2} d^{2} - 60 \, a^{3} b c d^{3} + 35 \, a^{4} d^{4}\right )} \sqrt {-b d} \arctan \left (\frac {{\left (2 \, b d x + b c + a d\right )} \sqrt {-b d} \sqrt {b x + a} \sqrt {d x + c}}{2 \, {\left (b^{2} d^{2} x^{2} + a b c d + {\left (b^{2} c d + a b d^{2}\right )} x\right )}}\right ) - 2 \, {\left (48 \, b^{4} d^{4} x^{3} - 9 \, b^{4} c^{3} d - 15 \, a b^{3} c^{2} d^{2} + 145 \, a^{2} b^{2} c d^{3} - 105 \, a^{3} b d^{4} + 8 \, {\left (9 \, b^{4} c d^{3} - 7 \, a b^{3} d^{4}\right )} x^{2} + 2 \, {\left (3 \, b^{4} c^{2} d^{2} - 46 \, a b^{3} c d^{3} + 35 \, a^{2} b^{2} d^{4}\right )} x\right )} \sqrt {b x + a} \sqrt {d x + c}}{384 \, b^{5} d^{3}}\right ] \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^2*(d*x+c)^(3/2)/(b*x+a)^(1/2),x, algorithm="fricas")

[Out]

[1/768*(3*(3*b^4*c^4 + 4*a*b^3*c^3*d + 18*a^2*b^2*c^2*d^2 - 60*a^3*b*c*d^3 + 35*a^4*d^4)*sqrt(b*d)*log(8*b^2*d
^2*x^2 + b^2*c^2 + 6*a*b*c*d + a^2*d^2 + 4*(2*b*d*x + b*c + a*d)*sqrt(b*d)*sqrt(b*x + a)*sqrt(d*x + c) + 8*(b^
2*c*d + a*b*d^2)*x) + 4*(48*b^4*d^4*x^3 - 9*b^4*c^3*d - 15*a*b^3*c^2*d^2 + 145*a^2*b^2*c*d^3 - 105*a^3*b*d^4 +
8*(9*b^4*c*d^3 - 7*a*b^3*d^4)*x^2 + 2*(3*b^4*c^2*d^2 - 46*a*b^3*c*d^3 + 35*a^2*b^2*d^4)*x)*sqrt(b*x + a)*sqrt
(d*x + c))/(b^5*d^3), -1/384*(3*(3*b^4*c^4 + 4*a*b^3*c^3*d + 18*a^2*b^2*c^2*d^2 - 60*a^3*b*c*d^3 + 35*a^4*d^4)
*sqrt(-b*d)*arctan(1/2*(2*b*d*x + b*c + a*d)*sqrt(-b*d)*sqrt(b*x + a)*sqrt(d*x + c)/(b^2*d^2*x^2 + a*b*c*d + (
b^2*c*d + a*b*d^2)*x)) - 2*(48*b^4*d^4*x^3 - 9*b^4*c^3*d - 15*a*b^3*c^2*d^2 + 145*a^2*b^2*c*d^3 - 105*a^3*b*d^
4 + 8*(9*b^4*c*d^3 - 7*a*b^3*d^4)*x^2 + 2*(3*b^4*c^2*d^2 - 46*a*b^3*c*d^3 + 35*a^2*b^2*d^4)*x)*sqrt(b*x + a)*s
qrt(d*x + c))/(b^5*d^3)]

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giac [B]  time = 1.28, size = 501, normalized size = 1.97 \begin {gather*} \frac {\frac {8 \, {\left (\sqrt {b^{2} c + {\left (b x + a\right )} b d - a b d} \sqrt {b x + a} {\left (2 \, {\left (b x + a\right )} {\left (\frac {4 \, {\left (b x + a\right )}}{b^{2}} + \frac {b^{6} c d^{3} - 13 \, a b^{5} d^{4}}{b^{7} d^{4}}\right )} - \frac {3 \, {\left (b^{7} c^{2} d^{2} + 2 \, a b^{6} c d^{3} - 11 \, a^{2} b^{5} d^{4}\right )}}{b^{7} d^{4}}\right )} - \frac {3 \, {\left (b^{3} c^{3} + a b^{2} c^{2} d + 3 \, a^{2} b c d^{2} - 5 \, a^{3} d^{3}\right )} \log \left ({\left | -\sqrt {b d} \sqrt {b x + a} + \sqrt {b^{2} c + {\left (b x + a\right )} b d - a b d} \right |}\right )}{\sqrt {b d} b d^{2}}\right )} c {\left | b \right |}}{b^{2}} + \frac {{\left (\sqrt {b^{2} c + {\left (b x + a\right )} b d - a b d} {\left (2 \, {\left (b x + a\right )} {\left (4 \, {\left (b x + a\right )} {\left (\frac {6 \, {\left (b x + a\right )}}{b^{3}} + \frac {b^{12} c d^{5} - 25 \, a b^{11} d^{6}}{b^{14} d^{6}}\right )} - \frac {5 \, b^{13} c^{2} d^{4} + 14 \, a b^{12} c d^{5} - 163 \, a^{2} b^{11} d^{6}}{b^{14} d^{6}}\right )} + \frac {3 \, {\left (5 \, b^{14} c^{3} d^{3} + 9 \, a b^{13} c^{2} d^{4} + 15 \, a^{2} b^{12} c d^{5} - 93 \, a^{3} b^{11} d^{6}\right )}}{b^{14} d^{6}}\right )} \sqrt {b x + a} + \frac {3 \, {\left (5 \, b^{4} c^{4} + 4 \, a b^{3} c^{3} d + 6 \, a^{2} b^{2} c^{2} d^{2} + 20 \, a^{3} b c d^{3} - 35 \, a^{4} d^{4}\right )} \log \left ({\left | -\sqrt {b d} \sqrt {b x + a} + \sqrt {b^{2} c + {\left (b x + a\right )} b d - a b d} \right |}\right )}{\sqrt {b d} b^{2} d^{3}}\right )} d {\left | b \right |}}{b^{2}}}{192 \, b} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^2*(d*x+c)^(3/2)/(b*x+a)^(1/2),x, algorithm="giac")

[Out]

1/192*(8*(sqrt(b^2*c + (b*x + a)*b*d - a*b*d)*sqrt(b*x + a)*(2*(b*x + a)*(4*(b*x + a)/b^2 + (b^6*c*d^3 - 13*a*
b^5*d^4)/(b^7*d^4)) - 3*(b^7*c^2*d^2 + 2*a*b^6*c*d^3 - 11*a^2*b^5*d^4)/(b^7*d^4)) - 3*(b^3*c^3 + a*b^2*c^2*d +
3*a^2*b*c*d^2 - 5*a^3*d^3)*log(abs(-sqrt(b*d)*sqrt(b*x + a) + sqrt(b^2*c + (b*x + a)*b*d - a*b*d)))/(sqrt(b*d
)*b*d^2))*c*abs(b)/b^2 + (sqrt(b^2*c + (b*x + a)*b*d - a*b*d)*(2*(b*x + a)*(4*(b*x + a)*(6*(b*x + a)/b^3 + (b^
12*c*d^5 - 25*a*b^11*d^6)/(b^14*d^6)) - (5*b^13*c^2*d^4 + 14*a*b^12*c*d^5 - 163*a^2*b^11*d^6)/(b^14*d^6)) + 3*
(5*b^14*c^3*d^3 + 9*a*b^13*c^2*d^4 + 15*a^2*b^12*c*d^5 - 93*a^3*b^11*d^6)/(b^14*d^6))*sqrt(b*x + a) + 3*(5*b^4
*c^4 + 4*a*b^3*c^3*d + 6*a^2*b^2*c^2*d^2 + 20*a^3*b*c*d^3 - 35*a^4*d^4)*log(abs(-sqrt(b*d)*sqrt(b*x + a) + sqr
t(b^2*c + (b*x + a)*b*d - a*b*d)))/(sqrt(b*d)*b^2*d^3))*d*abs(b)/b^2)/b

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maple [B]  time = 0.02, size = 574, normalized size = 2.26 \begin {gather*} \frac {\sqrt {d x +c}\, \sqrt {b x +a}\, \left (105 a^{4} d^{4} \ln \left (\frac {2 b d x +a d +b c +2 \sqrt {\left (b x +a \right ) \left (d x +c \right )}\, \sqrt {b d}}{2 \sqrt {b d}}\right )-180 a^{3} b c \,d^{3} \ln \left (\frac {2 b d x +a d +b c +2 \sqrt {\left (b x +a \right ) \left (d x +c \right )}\, \sqrt {b d}}{2 \sqrt {b d}}\right )+54 a^{2} b^{2} c^{2} d^{2} \ln \left (\frac {2 b d x +a d +b c +2 \sqrt {\left (b x +a \right ) \left (d x +c \right )}\, \sqrt {b d}}{2 \sqrt {b d}}\right )+12 a \,b^{3} c^{3} d \ln \left (\frac {2 b d x +a d +b c +2 \sqrt {\left (b x +a \right ) \left (d x +c \right )}\, \sqrt {b d}}{2 \sqrt {b d}}\right )+9 b^{4} c^{4} \ln \left (\frac {2 b d x +a d +b c +2 \sqrt {\left (b x +a \right ) \left (d x +c \right )}\, \sqrt {b d}}{2 \sqrt {b d}}\right )+96 \sqrt {\left (b x +a \right ) \left (d x +c \right )}\, \sqrt {b d}\, b^{3} d^{3} x^{3}-112 \sqrt {\left (b x +a \right ) \left (d x +c \right )}\, \sqrt {b d}\, a \,b^{2} d^{3} x^{2}+144 \sqrt {\left (b x +a \right ) \left (d x +c \right )}\, \sqrt {b d}\, b^{3} c \,d^{2} x^{2}+140 \sqrt {\left (b x +a \right ) \left (d x +c \right )}\, \sqrt {b d}\, a^{2} b \,d^{3} x -184 \sqrt {\left (b x +a \right ) \left (d x +c \right )}\, \sqrt {b d}\, a \,b^{2} c \,d^{2} x +12 \sqrt {\left (b x +a \right ) \left (d x +c \right )}\, \sqrt {b d}\, b^{3} c^{2} d x -210 \sqrt {\left (b x +a \right ) \left (d x +c \right )}\, \sqrt {b d}\, a^{3} d^{3}+290 \sqrt {\left (b x +a \right ) \left (d x +c \right )}\, \sqrt {b d}\, a^{2} b c \,d^{2}-30 \sqrt {\left (b x +a \right ) \left (d x +c \right )}\, \sqrt {b d}\, a \,b^{2} c^{2} d -18 \sqrt {b d}\, \sqrt {\left (b x +a \right ) \left (d x +c \right )}\, b^{3} c^{3}\right )}{384 \sqrt {\left (b x +a \right ) \left (d x +c \right )}\, \sqrt {b d}\, b^{4} d^{2}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(x^2*(d*x+c)^(3/2)/(b*x+a)^(1/2),x)

[Out]

1/384*(d*x+c)^(1/2)*(b*x+a)^(1/2)*(96*((b*x+a)*(d*x+c))^(1/2)*(b*d)^(1/2)*b^3*d^3*x^3-112*((b*x+a)*(d*x+c))^(1
/2)*(b*d)^(1/2)*a*b^2*d^3*x^2+144*((b*x+a)*(d*x+c))^(1/2)*(b*d)^(1/2)*b^3*c*d^2*x^2+105*a^4*d^4*ln(1/2*(2*b*d*
x+a*d+b*c+2*((b*x+a)*(d*x+c))^(1/2)*(b*d)^(1/2))/(b*d)^(1/2))-180*a^3*b*c*d^3*ln(1/2*(2*b*d*x+a*d+b*c+2*((b*x+
a)*(d*x+c))^(1/2)*(b*d)^(1/2))/(b*d)^(1/2))+54*a^2*b^2*c^2*d^2*ln(1/2*(2*b*d*x+a*d+b*c+2*((b*x+a)*(d*x+c))^(1/
2)*(b*d)^(1/2))/(b*d)^(1/2))+12*a*b^3*c^3*d*ln(1/2*(2*b*d*x+a*d+b*c+2*((b*x+a)*(d*x+c))^(1/2)*(b*d)^(1/2))/(b*
d)^(1/2))+9*b^4*c^4*ln(1/2*(2*b*d*x+a*d+b*c+2*((b*x+a)*(d*x+c))^(1/2)*(b*d)^(1/2))/(b*d)^(1/2))+140*((b*x+a)*(
d*x+c))^(1/2)*(b*d)^(1/2)*a^2*b*d^3*x-184*((b*x+a)*(d*x+c))^(1/2)*(b*d)^(1/2)*a*b^2*c*d^2*x+12*((b*x+a)*(d*x+c
))^(1/2)*(b*d)^(1/2)*b^3*c^2*d*x-210*((b*x+a)*(d*x+c))^(1/2)*(b*d)^(1/2)*a^3*d^3+290*((b*x+a)*(d*x+c))^(1/2)*(
b*d)^(1/2)*a^2*b*c*d^2-30*((b*x+a)*(d*x+c))^(1/2)*(b*d)^(1/2)*a*b^2*c^2*d-18*(b*d)^(1/2)*((b*x+a)*(d*x+c))^(1/
2)*b^3*c^3)/b^4/d^2/((b*x+a)*(d*x+c))^(1/2)/(b*d)^(1/2)

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maxima [F(-2)]  time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Exception raised: ValueError} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^2*(d*x+c)^(3/2)/(b*x+a)^(1/2),x, algorithm="maxima")

[Out]

Exception raised: ValueError >> Computation failed since Maxima requested additional constraints; using the 'a
ssume' command before evaluation *may* help (example of legal syntax is 'assume(a*d-b*c>0)', see `assume?` for
more details)Is a*d-b*c zero or nonzero?

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mupad [F]  time = 0.00, size = -1, normalized size = -0.00 \begin {gather*} \int \frac {x^2\,{\left (c+d\,x\right )}^{3/2}}{\sqrt {a+b\,x}} \,d x \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((x^2*(c + d*x)^(3/2))/(a + b*x)^(1/2),x)

[Out]

int((x^2*(c + d*x)^(3/2))/(a + b*x)^(1/2), x)

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sympy [F(-1)]  time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Timed out} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x**2*(d*x+c)**(3/2)/(b*x+a)**(1/2),x)

[Out]

Timed out

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